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2003 AMC 10 Past Papers

AMC 10 A/B · Overview · Practice · Prep

The 2003 AMC 10 Papers A and B emphasized algebraic evaluation and number-theory divisibility, with dense coverage of factor-counting, work-rate, average-speed and combinatorial-counting problems that raised the bar for accuracy and formula discrimination in the back half. Scan for the full papers and answer keys.

2003 AMC 10 Paper Overview

2003 AMC 10 A/B paper overview and exam highlights.

The 2003 AMC 10 was held in November 2003 in two papers (A and B), with algebraic evaluation and divisibility in number theory standing out.

Format: 25 multiple-choice questions, 75 minutes, 150 points max; a blank answer earns 1.5 points and a wrong answer earns 0. The AIME cut-off has recently been around 100 (Paper A).

The 2003 paper set more problems on divisor counts, work rates, average speed, and combinatorial counting, combining formulas with careful reading.

2003 AMC 10 Key Topics Tested

2003 AMC 10 main topic areas, weights and emphasis.

Algebra30%

Evaluation, quadratics, word and speed problems; about 30%.

Geometry22%

Rectangle perimeter, triangle area, cylinder surface area; about 22%.

Number Theory18%

Divisibility, remainders, GCD and divisor counts; about 18%.

Combinatorics20%

Coin outcomes, combinations and ordered counting; about 20%.

Probability10%

Classical probability and dice sums; about 10%.

25 Online Practice Questions

2003 AMC 10-style mock questions (Basic · Medium · Hard) — submit to grade and view step-by-step solutions.

Basic · Q1–10

1Algebra

If x = 4, what is the value of 3x2 - 2x + 1?

Correct answer: A

Substitute x = 4: 3(4)2 - 2(4) + 1 = 3×16 - 8 + 1 = 48 - 8 + 1 = 41. Answer A. Key: direct substitution.
2Algebra

The sum of three consecutive integers is 132. What is the largest?

Correct answer: B

Let the middle integer be n: 3n = 132, so n = 44 and the largest is 45. Answer B. Key: model consecutive integers by their middle.
3Number Theory

How many positive divisors does 240 have?

Correct answer: C

240 = 24×3×5, so the number of divisors is (4+1)(1+1)(1+1) = 20. Answer C. Key: divisor-count formula.
4Geometry

A rectangle has length 12 and width 2. What is its perimeter?

Correct answer: D

Perimeter = 2(12 + 2) = 2×14 = 28. Answer D. (24 is length + width — do not confuse.) Key: rectangle perimeter formula.
5Algebra

An item is marked up 35% above cost to a price of $81. What was the cost?

Correct answer: E

cost × 1.35 = 81, so cost = 81 / 1.35 = 60. Answer E. Key: price = cost × (1 + markup).
6Probability

A fair six-sided die is rolled once. What is the probability of rolling an odd number (1, 3, or 5)?

Correct answer: A

Odd values are 1, 3, 5 (3 of 6), so the probability is 3/6 = 1/2. Answer A. Key: classical probability = favorable / total.
7Combinatorics

Five coins are tossed at once. How many heads/tails outcomes are possible?

Correct answer: B

Each coin has 2 outcomes, so 5 coins give 25 = 32. Answer B. Key: independent outcomes multiply.
8Number Theory

What is the remainder when 2003 is divided by 9?

Correct answer: C

9 × 222 = 1998, and 2003 - 1998 = 5, so the remainder is 5. Answer C. Key: division with remainder.
9Algebra

If 4x + 9 = 33, what is x?

Correct answer: D

4x = 33 - 9 = 24, so x = 6. Answer D. Key: isolate the variable.
10Geometry

A triangle has base 14 and height 5. What is its area?

Correct answer: E

Area = ½×14×5 = 70/2 = 35. Answer E. Key: triangle area formula.

Medium · Q11–20

11Algebra

If x2 - 10x + 24 = 0, what is the sum of all possible values of x?

Correct answer: A

Factor: (x-4)(x-6) = 0, so x = 4 or 6, and the sum is 10. Answer A. Key: Vieta — sum of roots = -b/a = 10.
12Number Theory

What is the greatest common divisor of 48 and 64?

Correct answer: B

48 = 24×3 and 64 = 26, so GCD = 24 = 16. Answer B. Key: take the smallest power of each shared prime.
13Combinatorics

A committee of 2 is chosen from 27 people. How many different committees are possible?

Correct answer: C

C(27,2) = (27×26)/(2×1) = 351. Answer C. Key: combinations are order-independent, C(n,k) = n!/(k!(n-k)!).
14Geometry

In a triangle, two angles are 30° and 70°. What is the third angle?

Correct answer: D

Triangle angles sum to 180°, so the third angle = 180 - 30 - 70 = 80°. Answer D. Key: triangle angle-sum theorem.
15Algebra

The average of 8 numbers is 15. After removing one number, the average of the remaining 7 is 13. What was the removed number?

Correct answer: E

Sum of 8 = 8×15 = 120; sum of 7 = 7×13 = 91; the removed number = 120 - 91 = 29. Answer E. Key: average = sum / count.
16Number Theory

What is the units digit of 72003?

Correct answer: A

The units digit of powers of 7 cycles as 7, 9, 3, 1 (period 4). Since 2003 = 4×500 + 3, the remainder is 3, corresponding to the 3rd value, so the units digit is 3. Answer A. Key: cyclic units digits of powers.
17Algebra

One worker can finish a job in 12 hours and another in 36 hours. How long does it take them together?

Correct answer: B

Rates: 1/12 + 1/36 = 3/36 + 1/36 = 4/36 = 1/9 per hour, so together they need 1 / (1/9) = 9 hours. Answer B. Key: combined rate = sum of individual rates.
18Geometry

A square and an equilateral triangle have the same perimeter. If the triangle side is 84, what is the square side?

Correct answer: C

Triangle perimeter = 3×84 = 252, so the square side = 252 / 4 = 63. Answer C. Key: equal perimeters split by side count.
19Probability

Two fair six-sided dice are rolled. What is the probability the sum is 11?

Correct answer: D

Sums to 11: (5,6),(6,5) — 2 outcomes out of 36, so 2/36 = 1/18. Answer D. Key: enumerate ordered dice pairs.
20Algebra

A car travels 60 km at 20 km/h and returns at 30 km/h. What is the average speed for the whole trip (km/h)?

Correct answer: E

Outbound time = 60/20 = 3 h; return = 60/30 = 2 h. Total distance 120 km over 5 h gives 120/5 = 24 km/h. Answer E. Key: average speed = total distance / total time, not the average of speeds.

Hard · Q21–25

21Number Theory

How many positive integers less than 100 are divisible by both 7 and 14?

Correct answer: A

Divisible by both 7 and 14 means divisible by LCM(7,14) = 14. The multiples of 14 below 100 are 14, 28, 42, 56, 70, 84, 98 — 7 of them. Answer A. Key: divisible by both ⟺ divisible by their LCM.
22Combinatorics

A committee of 2 is chosen from 11 people. How many different committees are possible?

Correct answer: B

C(11,2) = (11×10)/(2×1) = 55. Answer B. Key: combinations are order-independent, C(n,k) = n!/(k!(n-k)!).
23Geometry

A right cylinder has radius 5 and height 5. What is its total surface area? (in terms of π)

Correct answer: C

Surface area = 2πr2 + 2πrh = 2π(52) + 2π(5)(5) = 50π + 50π = 100π. Answer C. Key: cylinder surface = two bases + lateral area.
24Algebra

Given x + y = 31 and xy = 240, what is x2 + y2?

Correct answer: D

x2 + y2 = (x+y)2 - 2xy = 312 - 2×240 = 961 - 480 = 481. Answer D. Key: identity linking sum of squares to sum and product.
25Combinatorics

In how many ways can 32 be written as a sum of three positive integers, where order does not matter?

Correct answer: E

Let a ≤ b ≤ c with a+b+c = 32. For a=1: 15 ways — (1,1,30) to (1,15,16); a=2: 14 ways — (2,2,28) to (2,15,15); a=3: 12 ways — (3,3,26) to (3,14,15); a=4: 11 ways — (4,4,24) to (4,14,14); a=5: 9 ways — (5,5,22) to (5,13,14); a=6: 8 ways — (6,6,20) to (6,13,13); a=7: 6 ways — (7,7,18) to (7,12,13); a=8: 5 ways — (8,8,16) to (8,12,12); a=9: 3 ways — (9,9,14) to (9,11,12); a=10: 2 ways — (10,10,12) to (10,11,11). Total 85. Answer E. Key: ordered enumeration to avoid duplicates.

2003 AMC 10 Format

Unified AMC 10 specs, consistent across years.

Questions & Scoring25 multiple-choice; +6 correct, +1.5 blank, 0 wrong; max 150
Duration75 minutes
PapersPapers A & B, comparable; take either or both, higher counts
EligibilityGrade 10 and below; under 17.5 on test day
AdvancementMeeting the cut-off qualifies for AIME

Papers A & B

Papers A and B are comparable in difficulty and scope. Students may take either, or both — the higher score is used for awards and AIME qualification.

How to Use This Page

Four steps · Overview / Topics / Practice / Prep

1

Paper Overview

Read the 2003 AMC 10 A/B overview and format specs to grasp the year’s style.

2

Find Topics

Review the key topics and weights, and locate your weak areas.

3

Take the Quiz

Complete the 25 mock questions (75-minute limit); submit for auto-grading and right/wrong marks.

4

Review & Prep

Open the step-by-step solutions, learn from mistakes, and scan for full papers to push for AIME.

2003 AMC 10 Prep Guide

Prep tips and score-boosting advice for the 2003 AMC 10 A/B paper.

1

Timed Mock Exams

Finish all 25 within 75 minutes; skip when stuck, bank the solvable ones, and return to the hard ones.

2

Divisor Counts

Factor N into prime powers; the divisor count is the product of (exponent + 1).

3

Combined Work Rates

Combined rate = sum of individual rates; time = 1 / combined rate.

4

Average Speed

Average speed = total distance / total time — never the arithmetic mean of the two speeds.

5

Push for AIME

Aiming above 100? Lock the basics and medium questions, then take the last 5 step by step; scan for full papers and a plan.

2003 AMC 10 Past Paper FAQ

Frequent questions about the 2003 AMC 10 papers and answers.

This page archives the 2003 AMC 10 A/B paper entries. Paper and answer files are placeholders — scan to consult the advisor for full materials.
Yes. The 2003 AMC 10 has Papers A and B, comparable in difficulty, held on separate dates. You may take one or both; the higher score counts for awards and AIME qualification.
Papers and answer keys are compiled after the exam. The answer entry on this page is a placeholder — scan to get the answer key and step-by-step solutions first.
The two papers are comparable in difficulty and scope, differing only in date and specific questions. You may take either or both; the higher score is used for awards and AIME qualification.
Practice past papers under time limits, drill by topic, and review mistakes against the answer key. To reach the AIME cut-off, consider 1-on-1 coaching — scan for a custom plan.

Start 2003 AMC 10 Prep

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