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2005 AMC 10 Past Papers

AMC 10 A/B · Overview · Practice · Prep

The 2005 AMC 10 Papers A and B continued the algebraic-evaluation and number-theory-divisibility thrust, with staple problems on factor-counting, coin outcomes, units digits and average speed testing fluency with core formulas and conceptual discrimination. Scan for the full papers and answer keys.

2005 AMC 10 Paper Overview

2005 AMC 10 A/B paper overview and exam highlights.

The 2005 AMC 10 was held in November 2005 in two papers (A and B), fairly balanced between algebraic evaluation and divisibility in number theory.

Format: 25 multiple-choice questions, 75 minutes, 150 points max; a blank answer earns 1.5 points and a wrong answer earns 0. The AIME cut-off has recently been around 100 (Paper A).

The 2005 paper set more problems on divisor counts, coin outcomes, units digits of powers, and average speed, combining formulas with careful reading.

2005 AMC 10 Key Topics Tested

2005 AMC 10 main topic areas, weights and emphasis.

Algebra28%

Evaluation, quadratics, word and speed problems; about 28%.

Geometry23%

Rectangle perimeter, triangle area, cylinder surface area; about 23%.

Number Theory19%

Divisibility, remainders, GCD and divisor counts; about 19%.

Combinatorics20%

Coin outcomes, combinations and ordered counting; about 20%.

Probability10%

Classical probability and dice sums; about 10%.

25 Online Practice Questions

2005 AMC 10-style mock questions (Basic · Medium · Hard) — submit to grade and view step-by-step solutions.

Basic · Q1–10

1Algebra

If x = 2, what is the value of 3x2 + 4x - 2?

Correct answer: A

Substitute x = 2: 3(2)2 + 4(2) - 2 = 3×4 + 8 - 2 = 12 + 8 - 2 = 18. Answer A. Key: direct substitution.
2Algebra

The sum of three consecutive integers is 126. What is the largest?

Correct answer: B

Let the middle integer be n: 3n = 126, so n = 42 and the largest is 43. Answer B. Key: model consecutive integers by their middle.
3Number Theory

How many positive divisors does 144 have?

Correct answer: C

144 = 24×32, so the number of divisors is (4+1)(2+1) = 15. Answer C. Key: divisor-count formula.
4Geometry

A rectangle has length 10 and width 4. What is its perimeter?

Correct answer: D

Perimeter = 2(10 + 4) = 2×14 = 28. Answer D. (40 is the area — do not confuse.) Key: rectangle perimeter formula.
5Algebra

An item is marked up 30% above cost to a price of $78. What was the cost?

Correct answer: E

cost × 1.3 = 78, so cost = 78 / 1.3 = 60. Answer E. Key: price = cost × (1 + markup).
6Probability

A fair six-sided die is rolled once. What is the probability of rolling at least 5 (5 or 6)?

Correct answer: A

Values at least 5 are 5 and 6 (2 of 6), so the probability is 2/6 = 1/3. Answer A. Key: classical probability = favorable / total.
7Combinatorics

Four coins are tossed at once. How many heads/tails outcomes are possible?

Correct answer: B

Each coin has 2 outcomes, so 4 coins give 24 = 16. Answer B. Key: independent outcomes multiply.
8Number Theory

What is the remainder when 2005 is divided by 7?

Correct answer: C

7 × 286 = 2002, and 2005 - 2002 = 3, so the remainder is 3. Answer C. Key: division with remainder.
9Algebra

If 6x + 5 = 41, what is x?

Correct answer: D

6x = 41 - 5 = 36, so x = 6. Answer D. Key: isolate the variable.
10Geometry

A triangle has base 11 and height 6. What is its area?

Correct answer: E

Area = ½×11×6 = 66/2 = 33. Answer E. Key: triangle area formula.

Medium · Q11–20

11Algebra

If x2 - 14x + 48 = 0, what is the sum of all possible values of x?

Correct answer: A

Factor: (x-6)(x-8) = 0, so x = 6 or 8, and the sum is 14. Answer A. Key: Vieta — sum of roots = -b/a = 14.
12Number Theory

What is the greatest common divisor of 60 and 84?

Correct answer: B

60 = 22×3×5 and 84 = 22×3×7, so GCD = 22×3 = 12. Answer B. Key: take the smallest power of each shared prime.
13Combinatorics

A committee of 2 is chosen from 16 people. How many different committees are possible?

Correct answer: C

C(16,2) = (16×15)/(2×1) = 120. Answer C. Key: combinations are order-independent, C(n,k) = n!/(k!(n-k)!).
14Geometry

In a triangle, two angles are 35° and 55°. What is the third angle?

Correct answer: D

Triangle angles sum to 180°, so the third angle = 180 - 35 - 55 = 90°. Answer D. Key: triangle angle-sum theorem.
15Algebra

The average of 6 numbers is 20. After removing one number, the average of the remaining 5 is 18. What was the removed number?

Correct answer: E

Sum of 6 = 6×20 = 120; sum of 5 = 5×18 = 90; the removed number = 120 - 90 = 30. Answer E. Key: average = sum / count.
16Number Theory

What is the units digit of 72005?

Correct answer: A

The units digit of powers of 7 cycles as 7, 9, 3, 1 (period 4). Since 2005 = 4×501 + 1, the remainder is 1, corresponding to the 1st value, so the units digit is 7. Answer A. Key: cyclic units digits of powers.
17Algebra

One worker can finish a job in 10 hours and another in 40 hours. How long does it take them together?

Correct answer: B

Rates: 1/10 + 1/40 = 4/40 + 1/40 = 5/40 = 1/8 per hour, so together they need 1 / (1/8) = 8 hours. Answer B. Key: combined rate = sum of individual rates.
18Geometry

A square and an equilateral triangle have the same perimeter. If the triangle side is 48, what is the square side?

Correct answer: C

Triangle perimeter = 3×48 = 144, so the square side = 144 / 4 = 36. Answer C. Key: equal perimeters split by side count.
19Probability

Two fair six-sided dice are rolled. What is the probability the sum is 10?

Correct answer: D

Sums to 10: (4,6),(5,5),(6,4) — 3 outcomes out of 36, so 3/36 = 1/12. Answer D. Key: enumerate ordered dice pairs.
20Algebra

A car travels 180 km at 30 km/h and returns at 90 km/h. What is the average speed for the whole trip (km/h)?

Correct answer: E

Outbound time = 180/30 = 6 h; return = 180/90 = 2 h. Total distance 360 km over 8 h gives 360/8 = 45 km/h. Answer E. Key: average speed = total distance / total time, not the average of speeds.

Hard · Q21–25

21Number Theory

How many positive integers less than 100 are divisible by both 4 and 10?

Correct answer: A

Divisible by both 4 and 10 means divisible by LCM(4,10) = 20. The multiples of 20 below 100 are 20, 40, 60, 80 — 4 of them. Answer A. Key: divisible by both ⟺ divisible by their LCM.
22Combinatorics

A committee of 3 is chosen from 9 people. How many different committees are possible?

Correct answer: B

C(9,3) = (9×8×7)/(3×2×1) = 504/6 = 84. Answer B. Key: combinations are order-independent, C(n,k) = n!/(k!(n-k)!).
23Geometry

A right cylinder has radius 6 and height 2. What is its total surface area? (in terms of π)

Correct answer: C

Surface area = 2πr2 + 2πrh = 2π(62) + 2π(6)(2) = 72π + 24π = 96π. Answer C. Key: cylinder surface = two bases + lateral area.
24Algebra

Given x + y = 29 and xy = 210, what is x2 + y2?

Correct answer: D

x2 + y2 = (x+y)2 - 2xy = 292 - 2×210 = 841 - 420 = 421. Answer D. Key: identity linking sum of squares to sum and product.
25Combinatorics

In how many ways can 30 be written as a sum of three positive integers, where order does not matter?

Correct answer: E

Let a ≤ b ≤ c with a+b+c = 30. For a=1: 14 ways — (1,1,30) to (1,14,15); a=2: 13 ways — (2,2,26) to (2,14,14); a=3: 11 ways — (3,3,24) to (3,13,14); a=4: 10 ways — (4,4,22) to (4,13,13); a=5: 8 ways — (5,5,20) to (5,12,13); a=6: 7 ways — (6,6,18) to (6,12,12); a=7: 5 ways — (7,7,16) to (7,11,12); a=8: 4 ways — (8,8,14) to (8,11,11); a=9: 2 ways — (9,9,12) to (9,10,11); a=10: 1 way — (10,10,10). Total 75. Answer E. Key: ordered enumeration to avoid duplicates.

2005 AMC 10 Format

Unified AMC 10 specs, consistent across years.

Questions & Scoring25 multiple-choice; +6 correct, +1.5 blank, 0 wrong; max 150
Duration75 minutes
PapersPapers A & B, comparable; take either or both, higher counts
EligibilityGrade 10 and below; under 17.5 on test day
AdvancementMeeting the cut-off qualifies for AIME

Papers A & B

Papers A and B are comparable in difficulty and scope. Students may take either, or both — the higher score is used for awards and AIME qualification.

How to Use This Page

Four steps · Overview / Topics / Practice / Prep

1

Paper Overview

Read the 2005 AMC 10 A/B overview and format specs to grasp the year’s style.

2

Find Topics

Review the key topics and weights, and locate your weak areas.

3

Take the Quiz

Complete the 25 mock questions (75-minute limit); submit for auto-grading and right/wrong marks.

4

Review & Prep

Open the step-by-step solutions, learn from mistakes, and scan for full papers to push for AIME.

2005 AMC 10 Prep Guide

Prep tips and score-boosting advice for the 2005 AMC 10 A/B paper.

1

Timed Mock Exams

Finish all 25 within 75 minutes; skip when stuck, bank the solvable ones, and return to the hard ones.

2

Divisor Counts

Factor N into prime powers; the divisor count is the product of (exponent + 1).

3

Units Digits of Powers

Units digits cycle by the base; locate the result via the exponent mod the period.

4

Average Speed

Average speed = total distance / total time — never the arithmetic mean of the two speeds.

5

Push for AIME

Aiming above 100? Lock the basics and medium questions, then take the last 5 step by step; scan for full papers and a plan.

2005 AMC 10 Past Paper FAQ

Frequent questions about the 2005 AMC 10 papers and answers.

This page archives the 2005 AMC 10 A/B paper entries. Paper and answer files are placeholders — scan to consult the advisor for full materials.
Yes. The 2005 AMC 10 has Papers A and B, comparable in difficulty, held on separate dates. You may take one or both; the higher score counts for awards and AIME qualification.
Papers and answer keys are compiled after the exam. The answer entry on this page is a placeholder — scan to get the answer key and step-by-step solutions first.
The two papers are comparable in difficulty and scope, differing only in date and specific questions. You may take either or both; the higher score is used for awards and AIME qualification.
Practice past papers under time limits, drill by topic, and review mistakes against the answer key. To reach the AIME cut-off, consider 1-on-1 coaching — scan for a custom plan.

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